Download MH-CET Previous Year Question Paper 2022 from links below:
Download Physics Shift-I | Click here |
Download Physics Shift-II | Click here |
Download Chemistry Shift-I | Click here |
Download Chemistry Shift – II | Click here |
Download Maths Shift-I | Click here |
Downlaod Maths shift -II | Click here |
Download Biology Shift-I | Click here |
MHT-CET PHYSICS Paper Shift-II with Solutions
MHT-CET Chemistry Paper Shift-II with Solutions
MHT-CET Mathematics Paper Shift-II with Solutions
11TH AUGUST (SHIFT – 2) Solutions
Q.1 ) The magnetic susceptibility of the material of a rod is 349 and permeability of vacuum μ0​ is 4π ×10–7 SI units .Absolute permeability of the material of the rod in SI units
(a) 4400 × 10–7 (b) 4200 × 10–7
(c) 4800 × 10–7 (d) 4600 × 10–7
Ans : a
Solutions :
The relative permeability μR = 1 + χ
Absolute permeability μ = μRμ0 = μ0(1+ χ )
= 4π × 10–7 [1 + 349]
= 350 × 4 × 3.142 × 10–7
= 4400 × 10–7 SI units
Q.2 ) The magnetic flux through a coil of resistance ‘R’ changes by an amount ‘Δϕ‘ in time ‘Δt’. The total quantity of induced electric charge ‘Q’ is
a) -\frac{\Delta \phi}{ Δt} +R
b ) \frac{\Delta \phi}{ Δt} \times R
c ) \frac{\Delta \phi}{ R}
d ) \frac{\Delta \phi}{ Δt}
Ans : C
Solutions :
By \, faraday \, law, \\ e=\ \frac{\Delta \phi}{ Δt} \\ \, \\ i = \frac{e}{ R} = \frac{\Delta \phi}{ R\Delta t} \\ \, \\ \, (i)\Delta t =\frac{ \Delta \phi}{R} \quad-(1) \\ \, \\but \, i = \frac{\Delta Q}{ Δt} ,\, { Δt} = i{ Δt} \\ \,\\ from \,eq(1) , \Delta Q= \frac{\Delta \phi}{ R} \\ \, \\ Q = \frac{\Delta \phi}{ R}